8a^2-18a+9=0

Solution for 8a^2-18a+9=0 equation:

8a^2-18a+9=0

a = 8; b = -18; c = +9;
Δ = b2-4ac
Δ = -182-4·8·9
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6}{2*8}=\frac{12}{16}
=3/4
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6}{2*8}=\frac{24}{16}
=1+1/2
$